ACCELERATIONS OF GALAXIES……AN APPLICATION OF EQUATIONS OF MOTIONS

ACCELERATIONS OF GALAXIES……AN APPLICATION  OF EQUATIONS OF MOTIONS.

NAME OF THEORETICAL PARTICLE ASTROPHYSICIST : MUNISHKUMAR.B.CHINNAKAR.

             

PLACE OF INVENTIONS: MUNISHKUMAR.B.C’S FIRST FLOOR BUILDING NEAR BHAIRI WELL BOYER STREET,SHORAPUR,PIN:585224 DIST:YADAGEER,KARNATAKA STATE INDIA.

                   

CO-WORKERS:NO CO-WORKERS.

DATE  OF INVENTIONS:26,MARCH,2016

DATE  OF ENTRY OF INVENTIONS:MARCH,26,2016

PAPER NO: PAPFMJ/QGP 66/4421.

Equations of motions as described by Newton were correct but as such force Equation will not describe anything regarding force distribution during motion.Further they are not correctly describing the acceleration of Galaxies.Therefore My modified equations of Motions[1] are useful.These modified equations of motions can be used to calculate self rotational acceleration and linear acceleration of different Galaxies(The values calculated are consistent with other equations of motion like centripetal/centrifugal motions).This is as follows.

(A)LINEAR ACCELERATION OF GALAXIES due to

The Galaxy moves due to its own gravity field as energy.Most of the galaxies are moving independently of other galaxies.Due to motion of Stars and Planets and also due to motion of stellar systems,configuration of Gravity field changes around the Galaxy.This results in change in its velocity.Therefore Galaxy accelerates.The force which it moves this Galaxy  is related to its velocity[2] by the following equation.

             1/2(MV^2)=FxDx1.6…………(01)

This gives a force F=[1/2(MV^2)]/Dx1.6.But this force is purely gravitational but in presence of Self Galaxy’s  Radiation this becomes

F=[1/2(MV^2)]x10^3/(Dx1.6)………..(02)Here Transformation constant of Unity type for the transformation of Matter to radiation like C=10^3=1 is utilized.

In case of Milky way Galaxy,m=1. 988x10^30x1.5x10^12kg, V=linear velocity of Galaxy in rarermost free space=5.58x10^5m/s,D=gravity field limiting value of Milky way Galaxy=180kly(value taken from Wikipedia).Therefore using (02) force becomes 1.7027x10^35N.

This is the real force with which a Milky way like Galaxy linearly moves for certain number of years.The acceleration of Galaxy during its motion can be calculated using equation

 Linear acceleration of Galaxy=a= F/M………(03),

where F is the value from equation (02).Thus in case of Milky way a=(1/a)/(10x10)=1.7512x10^5m/s^2

The Milky way is moving with acceleration 1.7512x10^5m/s^2.Thus using equation (03) with modification as in (02) with correction can be used for the calculation of acceleration of a Galaxy during its motion.

(B)ROTATIONAL ACCELERATION OF GALAXY.

The Galaxy rotates around itself .Here it chooses the value like linear acceleration as rotational velocity with modification  .In case of Milky way it is 1.7512x10^5x10^3m/S.The force which rotates this Galaxy is related to its modified value of roational velocity(energy equivalence of radiation is considered) by the following equation.

             1/2(MV^2)=F’xDx1.6…………(04)

This gives a force F’=[1/2(MV^2)]/Dx1.6.But this force is purely gravitational but in presence of Galactic ’s  Radiation[3] this becomes

F’=[1/2(MV^2)]x10^3x10^3/(Dx10^-4x1.6)………..(05)

In case of Milky way,m=1.5x10^12x1.988x!0^30kg,V=rotational  velocity of Milky way around itself=1.7512x10^5x10^3m/s=,D=Diameter of Milky way=180x10^3x9.467x10^15m.Therefore using (05) force becomes 1.67x10^47N.

This is the real force with which a Galaxy like Milky way rotates around itself.The acceleration of Milky way during its rotational motion can be calculated using equation

Rotating acceleration of Milky way=a= F’/M………(06),

where F’ is the value from equation (05).Thus in case of Milky way a=1.67x10^47N/(1.5x10^12x1.988x10^30)kg=0.5613x10^5m/s^2=56.13km/s^2.

The Milky way  is rotatinging around itself with  acceleration like a=56.13km/s^2 .Thus using equation (06) with modification as in (05)  can be used for the calculation of rotational acceleration of a Galaxy itself.

This acceleration like 56.13km/s^2 links to the value like acceleration due to gravity of Milky way.Here gravitating nature is useful ,therefore g=10x56.13km/s^2=561.3km/s^2. Above method of Calculation is useful for calculations of accelerations of different Galaxies.

NOTE:Equation (06) is consistent with equations like MV^2/R=F=Mxa (with modification to this for consistency using useful reasons).In the above example of Milky way,.In case (B)  [(10^3)^4]xMV^2/R

         

         

REFERENCES:

[1] EQUATIONS OF MOTIONS

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  07/03/2016

  [2] MILKY WAY BY WIKIPEDIA,UPDATED DURING 2016

[3] ACCELERATION DUE TO GRAVITY OF STARS-PROTON/NETRON STAR

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  06/12/2014

ACCELERATIONS OF STARS……AN APPLICATION OF EQUATIONS OF MOTIONS.

ACCELERATIONS OF STARS……AN APPLICATION  OF EQUATIONS OF MOTIONS.

NAME OF THEORETICAL PARTICLE ASTROPHYSICIST : MUNISHKUMAR.B.CHINNAKAR.

             

PLACE OF INVENTIONS: MUNISHKUMAR.B.C’S FIRST FLOOR BUILDING NEAR BHAIRI WELL BOYER STREET,SHORAPUR,PIN:585224 DIST:YADAGEER,KARNATAKA STATE INDIA.

                   

CO-WORKERS:NO CO-WORKERS.

DATE  OF INVENTIONS:25,MARCH,2016

DATE  OF ENTRY OF INVENTIONS:MARCH,25,2016

PAPER NO: PAPFMJ/QGP 65/4420.

Equations of motions as described by Newton were correct but as such force Equation will not describe anything regarding force distribution during motion.Further they are not correctly describing the acceleration of Stars.Therefore My modified equations of Motions[1] are useful.These modified equations of motions can be used to calculate self rotational acceleration and revolving acceleration of different Stars around Galactic centre(The values calculated are consistent with other equations of motion like centripetal/centrifugal motions).This is as follows.

(A)REVOLVING ACCELERATION OF STARS

The Star revolves around a Galactic centre like Sun due to gravity field of Milky way’s galactic centre(when it is alone it would have been moved due to self motion).Here it chooses the value like acceleration due to gravity of star at the place of Star.The force which it moves this Star  is related to its velocity[2] by the following equation.

             1/2(MV^2)=FxDx1.6…………(01)

This gives a force F=[1/2(MV^2)]/Dx1.6.But this force is purely gravitational but in presence of Star’s and cluster of star’s radiation  Radiation this becomes

F=[1/2(MV^2)]x10^3x10^3/(Dx1.6)………..(02)Here Transformation constant of Unity type for the transformation of Matter to radiation like C=10^3=1 is utilized.

In case of Sun,m=1.988x10^30kg,V=revolving velocity of Sun around Galactic centre=220km/s=2.2x10^5m/s,D=gravity field limiting[2] value of Galaxy=50000A.U=7.1000x10^15m(value taken from Wikipedia,as Solar system grown from its primary state).Therefore using (02) force becomes 2.1127x10^30N.

This is the real force with which a Star like Sun revolves around the Milky way’s Galactic Centre.The acceleration of Star during its revolving motion can be calculated using equation

Revolving acceleration of Star=a= F/M………(03),

where F is the value from equation (02).Thus in case of Sun a=1.0617m/s^2

The Sun is revolving around the Galactic centre with acceleration 1.0617m/s^2.Thus using equation (03) with modification as in (02) can be used for the calculation of revolving acceleration of a Star around Galactic centre.

(B)ROTATIONAL ACCELERATION OF STAR

The Star rotates around itself .Here it chooses the value like rotational velocity of Star.In case of Sun it is 1.99m/S.The above acceleration transforms as velocity like 1.0617x2=2.125m/s.This is the rotational velocity.The force which it rotates this Star is related to its modified value of roational velocity=2.125x10^3(energy equivalence of radiation is considered) by the following equation.

             1/2(MV^2)=F’xDx1.6…………(04)

This gives a force F’=[1/2(MV^2)]/Dx1.6.But this force is purely gravitational but in presence of Star’s and cluster of star’s Radiation[3] this becomes

F’=[1/2(MV^2)]x10^3x10^3/(Dx10^-4x1.6)………..(05)

In case of Sun,m=1.988x10^30kg,V=rotational  velocity of Sun around itself=2.125x10^3m/s=,D=Diameter of Sun=2x6.9070x10^8m.Therefore using (05) force becomes 2.0306x10^37N.

This is the real force with which a Star like Sun rotates around itself.The acceleration of Star during its rotational motion can be calculated using equation

Rotating acceleration of Star=a= F’/M………(06),

where F’ is the value from equation (05).Thus in case of Sun a=2.0306x10^37N/1.988x10^30kg=1.0214x10^7m/s^2

The Sun is rotatinging around itself with equivalent acceleration like a/C=1.0214x10^-1m/s^2 as 1.0214x10^7m/s^2.Thus using equation (06) with modification as in (05) and correction of moving mass as rest mass  can be used for the calculation of rotational acceleration of a Star itself.

This acceleration like 0.10214m/s^2 links to the value like acceleration due to gravity of Sun.Here gravitating 1D nature is useful via gravitational interaction like{ (1.0214x10^7)x1.1]/(10x4)=2.80x10^5m/s^2,here gravity interaction like 1.1 is taken into account.Therfore the value of g for Sun is 2.80x10^5m/s^2.From other method it is 2.7386x10^5m/s^2

Above method of Calculation is useful for calculations of accelerations of different Stars around Galactic centre.

NOTE:Equations (03) and (06) are consistent with equations like MV^2/R=F=Mxa (with modification to this for consistency using useful reasons).In the above example of Sun,in case of (A) MV^2/R  can be modified as [(π/2) x10^3x10x10x1.1x1.1]xMV^2/R.In case (B)  [(10x10^8)/( π/2)]xMV^2/R

         

         

REFERENCES:

[1] EQUATIONS OF MOTIONS

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  07/03/2016

  [2] EARTH BY WIKIPEDIA,UPDATED DURING 2016

[3] ACCELERATION DUE TO GRAVITY OF STARS-PROTON/NETRON STAR

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  06/12/2014

(MUNISHKUMAR.B.CHINNAKAR)

ACCELERATIONS OF NATURAL SATELITTES……AN APPLICATION OF EQUATIONS OF MOTIONS.

ACCELERATIONS OF NATURAL SATELITTES……AN APPLICATION  OF EQUATIONS OF MOTIONS.

NAME OF THEORETICAL PARTICLE ASTROPHYSICIST : MUNISHKUMAR.B.CHINNAKAR.

             

PLACE OF INVENTIONS: MUNISHKUMAR.B.C’S FIRST FLOOR BUILDING NEAR BHAIRI WELL BOYER STREET,SHORAPUR,PIN:585224 DIST:YADAGEER,KARNATAKA STATE INDIA.

                   

CO-WORKERS:NO CO-WORKERS.

DATE  OF INVENTIONS:23,MARCH,2016

DATE  OF ENTRY OF INVENTIONS:MARCH,24,2016

PAPER NO: PAPFMJ/QGP 64/4419.

Equations of motions as described by Newton were correct but as such force quation will not describe anything regarding force distribution during motion.Further they are not correctly describing the acceleration of Sateliites.Therefore My modified equations of Motions[1] are useful.These modified equations of motions can be used to calculate rotational acceleration and revolving acceleration of different Natural satellites around Planet and Star(The values calculated are consistent with other equations of motion like centripetal/centrifugal motions).This is as follows.

(A)REVOLVING ACCELERATION OF SATELITTE ARROUND SUN

The Satelitte revolves around a Planet like Earth  and also around Star due to gravity field of Star and Planet(when it is alone it would have been moved due to self motion).Here it chooses the value like acceleration due to gravity of star at the place of Satellite.In case of Earth /Moon[2] it is 6km/S^2.The force which it moves this planet is related to its velocity by the following equation.

             1/2(MV^2)=FxDx1.6…………(01)

This gives a force F=[1/2(MV^2)]/Dx1.6.But this force is purely gravitational but in presence of Star’s Radiation this becomes

F=[1/2(MV^2)]x10^3/Dx1.6………..(02)

In case of Moon,m=7.324x10^22kg,V=revolving velocity of Moon around Sun=30km/s=3x10^4m/s,D=gravity field limiting value of earth2.5x10^8m.Therefore using (02) force becomes 3.3039x10^25N.

This is the real force with which a Satelitte like Moon revolves around the Sun.The acceleration of Satelitte during its revolving motion can be calculated using equation

Revolving acceleration of Satelitte=a= F/M………(03),

where F is the value from equation (02).Thus in case of Moon a=3.3039x10^25N/7.324x10^22kg=450m/s^2

The Moon is revolving around the Sun with acceleration 450m/s^2.Thus using equation (03) with modification as in (02) can be used for the calculation of revolving acceleration of a Satellite around Star.

oses the value likerotational velocity of planet.In case of earth it is 436m/S.The force which it rotates this planet is related to its roational velocity by the following equation.

(B)REVOLVING ACCELERATION OF SATELITTE ARROUND EARTH

The Satelitte like Moon revolves around a Planet like Earth.The force with which it moves is related to velocity[3] by equation.

             1/2(MV^2)=F’xDx1.6…………(04)

This gives a force F’=[1/2(MV^2)]/Dx1.6.But this force is purely gravitational but in presence of Star’s Radiation this becomes

F’=[1/2(MV^2)]x10^3/Dx1.6………..(05)

In case of Moon,m=7.324x10^22kg,V=revolving velocity of Moon around Earth=1.022km/s=,D=gravity field limiting value of Moon=2.5x10^8m.Therefore using (05) force becomes 9.585x10^22N.

This is the real force with which a Satelitte like Moon revolves around the Earth.The acceleration of Satelitte during its revolving motion can be calculated using equation

Revolving acceleration of Satelitte=a= F’/M………(06),

where F’ is the value from equation (05).Thus in case of Moon a=9.585x10^22N/7.324x10^22kg=1.3m/s^2

The Moon is revolving around the Earth with acceleration 1.3m/s^2.Thus using equation (06) with modification as in (05) can be used for the calculation of revolving acceleration of a Satellite around Planet.

.

(C)ROTATIONAL ACCELERATION OF SATELITTE

The Satelitte rotates around itself .Here it chooses the value like rotational velocity of Satelite.In case of Moon it is 4.627m/S.The force which it rotates this planet is related to its roational velocity by the following equation.

             1/2(MV^2)=F’’xDx1.6…………(06)

This gives a force F’’=[1/2(MV^2)]/Dx1.6.But this force is purely gravitational but in presence of Star’s Radiation this becomes

F’’=[1/2(MV^2)]x10^3/Dx1.6………..(07)

In case of Moon m=7.324x10^22kg,V=rotational  velocity of Moon around itself=4.627m/s=,D=Diameter of Moon=1737.1x2x10^3m.Therefore using (07) force becomes 3.59x10^18N.

This is the real force with which a Satelitte like Moon rotates around itself.The acceleration of Satelitte during its rotational motion can be calculated using equation(07)

Rotating acceleration of Satelitte=a= F’’/M………(08),

where F’’ is the value from equation (07).Thus in case of Moon a=3.59x10^18N/7.3242x10^22kg=5x10^-5m/s^2

The Moon is rotatinging around itself with acceleration 5x10^-5m/s^2.Thus using equation (08) with modification as in (07) can be used for the calculation of rotational acceleration of a Satelitte itself.

The revolving acceleration of Moon like 450m/s^2 oscillates with interaction via contracting gravitating and regravitating nature yielding acceleration 450/(10x10)=4.5m/s^2.This then adds to gravitatively interacted revolving acceleration of Moon around Earth like 1.3/10. Therefore,For Moon at its vicinity acceleration becomes 4.5+1.3/10=4.63m/s^2.This becomes Roational velocity[3] of Moon around itself.

This rotational velocity around Moon itself links to its g as 4.63x2x(2)^1/2=13.09561/(4x2)=1.63m/S^2.This like 1D value of 4D.

NOTE:Equations (03) and (06) are consistent with equations like MV^2/R=F=Mxa (with modification to this for consistency using useful reasons).In the above example of Moon,in case of (A) MV^2/R  can be modified as [10^3x10x10/(2)^1/2]xMV^2/R.In case (B)  [(10^3)/(2X1.1)]xMV^2/R, in case of (C) MV^2/R  can be modified as [10/(10/4)]xMV^2/R.

         

         

REFERENCES:

[1] EQUATIONS OF MOTIONS

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  07/03/2016

  [2] ACCELERATION DUE TO GRAVITY OF STARS-PHOTON STAR

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  06/11/2014

  [3]MOON BY WIKIPEDIA,UPDATED DURING 2016

ACCELERATIONS OF PLANETS……AN APPLICATION OF EQUATIONS OF MOTIONS.

ACCELERATIONS OF PLANETS……AN APPLICATION  OF EQUATIONS OF MOTIONS.

NAME OF THEORETICAL PARTICLE ASTROPHYSICIST : MUNISHKUMAR.B.CHINNAKAR.

             

PLACE OF INVENTIONS: MUNISHKUMAR.B.C’S FIRST FLOOR BUILDING NEAR BHAIRI WELL BOYER STREET,SHORAPUR,PIN:585224 DIST:YADAGEER,KARNATAKA STATE INDIA.

                   

CO-WORKERS:NO CO-WORKERS.

DATE  OF INVENTIONS:05,MARCH,2016

DATE  OF ENTRY OF INVENTIONS:MARCH,20,2016
DATE  OF REENTRY OF INVENTIONS:MARCH,21,2016

PAPER NO: PAPFMJ/QGP 63/4418.

Equations of motions as described by Newton were correct but as such force quation will not describe anything regarding force distribution during motion.Further they are not correctly describing the acceleration of Planets.Therefore My modified equations of Motions[1] are useful.These modified equations of motions can be used to calculate rotational acceleration and revolving acceleration of different Planets around Star(The values calculated are consistent with other equations of motion like centripetal/centrifugal motions).This is as follows.

(A)REVOLVING ACCELERATION OF PLANET

The planet revolves around a star like Sun due to gravity field of Star(when it is alone it would have been moved due to self motion).Here it chooses the value like acceleration due to gravity of star at the place of Planet.In case of earth[2] it is 6km/S^2.The force which it moves this planet is related to its velocity[3] by the following equation.

             1/2(MV^2)=FxDx1.6…………(01)

This gives a force F=[1/2(MV^2)]/Dx1.6.But this force is purely gravitational but in presence of Star’s Radiation this becomes

F=[1/2(MV^2)]x10^3/Dx1.6………..(02)

In case of Earth,m=5.9x10^24kg,V=revolving velocity of Earth around Sun=30km/s=3x10^4m/s,D=gravity field limiting value of earth3.5x10^8m.Therefore using (02) force becomes 2.37x10^27N.

This is the real force with which a Planet like Earth revolves around the Sun.The acceleration of Planet during its revolving motion can be calculated using equation

Revolving acceleration of Planet=a= F/M………(03),

where F is the value from equation (02).Thus in case of Earth a=2.37x10^27N/5.9x10^24kg=4.01x10^2m/s^2

The Earth is revolving around the Sun with acceleration 4.01x10^2m/s^2.Thus using equation (03) with modification as in (02) can be used for the calculation of revolving acceleration of a Planet around Star.

(B)ROTATIONAL ACCELERATION OF PLANET

The planet rotates around itself .Here it chooses the value likerotational velocity of planet.In case of earth it is 436m/S.The force which it rotates this planet is related to its roational velocity by the following equation.

             1/2(MV^2)=FxDx1.6…………(04)

This gives a force F=[1/2(MV^2)]/Dx1.6.But this force is purely gravitational but in presence of Star’s Radiation this becomes

F=[1/2(MV^2)]x10^3/Dx1.6………..(05)

In case of Earth,m=5.9x10^24kg,V=rotational  velocity of Earth around itself=436m/s=,D=Diameter of Earth=1.2x10^7m.Therefore using (05) force becomes 2.9069x10^25N.

This is the real force with which a Planet like Earth rotates around itself.The acceleration of Planet during its rotational motion can be calculated using equation

Rotating acceleration of Planet=a= F/M………(06),

where F is the value from equation (05).Thus in case of Earth a=2.9069x10^27N/5.9x10^24kg=4.9503m/s^2

The Earth is rotatinging around itself with acceleration 4.950m/s^2.Thus using equation (06) with modification as in (05) can be used for the calculation of rotational acceleration of a Planet itself.

This acceleration like 4.950m/s^2 links to the value like acceleration due to gravity of earth.Here inertia of Earth acts and reacts(2) yielding a value like 4.950x2=9.8m/s^2,here gravity interaction like 1.1 is taken into account.Therfore the value of g for Earth is 9.8m/s^2

Above method of Calculation is useful for calculations of accelerations of different planets around Star.However 1D nature of Planet some times is a need for 1D planets.In the above accelerations for 4D acceleration like 401 m/s^2,4D value of acceleration due to gravity adds such that 401+(4x9.8)-4=436.2m/s^2.Thus revolving acceleration of Earth acts as rotational velocity.Therefore actually revolving acceleration oscillates and its interaction with g rotates the Earth.Therefore Spinning nature is not an Intrinsic property.

NOTE:Equations (03) and (06) are consistent with equations like MV^2/R=F=Mxa (with modification to this for consistency using useful reasons).In the above example of Earth,in case of (A) MV^2/R  can be modified as (4x10^3x10x10/2π)xMV^2/R.In case (B) (2π/2) x(10x10)xMV^2/R

         

         

REFERENCES:

[1] EQUATIONS OF MOTIONS

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  07/03/2016

  [2] ACCELERATION DUE TO GRAVITY OF STARS-PHOTON STAR

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  06/11/2014

   [3]EARTH,BY WIKIPEDIA,UPDATED DURING 2016

EQUATIONS OF MOTIONS

EQUATIONS OF MOTIONS

NAME OF THEORETICAL PARTICLE ASTROPHYSICIST : MUNISHKUMAR.B.CHINNAKAR.

             

PLACE OF INVENTIONS: MUNISHKUMAR.B.C’S FIRST FLOOR BUILDING NEAR BHAIRI WELL BOYER STREET,SHORAPUR,PIN:585224 DIST:YADAGEER,KARNATAKA STATE INDIA.

                   

CO-WORKERS:NO CO-WORKERS.

DATE  OF INVENTIONS:10,FEB,2016

DATE  OF ENTRY OF INVENTIONS:MARCH,07,2016

PAPER NO: PAPFMJ/QGP 62/4417.

      Everthing in this Universe is moving and their self motion can be described[1] by the following equations

(A)NON RELATIVISTIC MOTION

1/2MV^2=FxDx1.6

V=[(2xFxDx1.6)/M]^1/2…….(01) for 4D body/particle

AND

V=[{(2xFxDx1.6)/M}^1/2]/4…….(02) for 1D body/particle

 For the motion of Particle/body Force is a need in a free space(rarer most free energy space or inter galactic free space).This force in most of the cases like bodies  is self gravity force and in Particles it is due to gravity/Electric/Magnetic/Nuclear force and combination of these.

Equation (01) and (02) can be applied for Motion with an extra application of force in case of non-relativistic motion.

Here when F is the gravity force due to which body/particle moves then D is the range of influence of gravitational field of influence. When F is the Electric force due to which body/particle moves then D is the range of influence of electric field of influence. When F is the Magnetic force due to which body/particle moves then D is the range of influence of magnetic  field of influence. when F is the EM force due to which body/particle moves then D is the range of influence of EM force field of influence. When F is the Nuclear force due to which body/particle moves then D is the range of influence of Nuclear force field of influence. When F is the Dark force due to which body/particle moves then D is the range of influence of Dark force field of influence.Similerly for other foces corresponding range of influence D should be used.

(B) RELATIVISTIC MOTION

In case of relativistic motion(where velocity is greater than 10^5m/s).Equation takes the form

 (m-m0)C^2=FxDx1.6

Or

C= [(FxDx1.6)/ (m-m0)]^1/2……..(03) for 4D particle/body

And

C= [{(FxDx1.6)/ (m-m0)}^1/2]/4……..(04) for 1D particle/body

where m is observed mass from Einstein’s relation of special relativity and m0 is the rest mass.

Here when F is the gravity force due to which body/particle moves then D is the range of influence of gravitational field of influence. When F is the Electric force due to which body/particle moves then D is the range of influence of electric field of influence. When F is the Magnetic force due to which body/particle moves then D is the range of influence of magnetic  field of influence. when F is the EM force due to which body/particle moves then D is the range of influence of EM force field of influence. When F is the Nuclear force due to which body/particle moves then D is the range of influence of Nuclear force field of influence. When F is the Dark force due to which body/particle moves then D is the range of influence of Dark force field of influence.Similerly for other foces corresponding range of influence D should be used.

NOTE: ALONG WITH THIS MODIFIED NEWTON’S THIRD LAW SHOULD BE UTILISED IN CASE OF CONTRACTION/EXPANSION/CURVILINEAR MOTIONS.

         

REFERENCES:

[1] SELF MOTION IN FREE SPACE……GRAVITY AS THE REASON FOR MOTION

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  10/02/2016

  

(MUNISHKUMAR.B.CHINNAKAR.)

SELF MOTION IN FREE SPACE……GRAVITY AS THE REASON FOR MOTION

SELF MOTION IN FREE SPACE……GRAVITY AS THE REASON FOR MOTION

NAME OF THEORETICAL PARTICLE ASTROPHYSICIST : MUNISHKUMAR.B.CHINNAKAR.

             

PLACE OF INVENTIONS: MUNISHKUMAR.B.C’S FIRST FLOOR BUILDING NEAR BHAIRI WELL BOYER STREET,SHORAPUR,PIN:585224 DIST:YADAGEER,KARNATAKA STATE INDIA.

                   

CO-WORKERS:NO CO-WORKERS.

DATE  OF INVENTIONS:10,FEB,2016

DATE  OF ENTRY OF INVENTIONS:FEB,10,2016

PAPER NO: PAPFMJ/QGP 61/4416.

       For the motion of Particle/body Force is a need in a free space(rarer most free energy space or inter galactic free space).This force in most of the cases like bodies  is self gravity force and in Particles it is due to gravity/Electric/Magnetic/Nuclear force and combination of these[1].The relation for free motion in free space can be given by the equation,

1/2MV^2=FxDx1.6…………..(01)

This equation as such is valid for bodies with density 10^6kg/m^3.It takes modification for other density bodies.This is as follows.

(A)CASE OF MATTER[2]

(01)Case of Earth,Density=10^6Kg/m^3

Velocity calculated using this relation is 2.6855km/s,for Gravity force F=1.9x10^22N at distance D/2=3.5x10^8m=limiting gravity field of influence and mass=M=5.9x10^24Kg.,there is no modification in equation (01)

(02) Case of Electron,Density=10^24Kg/m^3

Velocity calculated using this relation is 5.05x10^-7m/s,for Gravity force F=5.56x10^-67N at distance D/2=1.1x10^-15m=Electromagnetic field of influence and mass=M=5.9x10^24Kg.Here equation takes a modification.When you get v from (01) ,take its square root,that is V=(V)^1/2,this is because,as density is 4D times velocity drops to square root times (this is related to force density relationships).

(B)CASE OF RADIATION[3]

(01)Case of photon,frequency=10^19Hz,Density=10^16 to10^19Kg/m^3

Velocity calculated using this relation is 3x10^8m/s,for Gravity force F=4.9x10^-41N at distance D/2=4.3x10^-17m=limiting gravity field of influence and mass=M=0.7361x10^-31Kg.,there is a modification in equation (01),here V=(1/V)X1.3X10^-4.

(A)CASE OF ENERGY[4]

(01)Case of Electron’s neutrino,Density=10^37Kg/m^3

Velocity calculated using this relation is 3x10^8m/s,for Gravity force F=2.1708x10^-30N at distance D/2=1x10^-21m=limiting gravity field of influence and mass=M=3.6x10^-36Kg.,there is a modification in equation (01),here V becomes (1/V)X3X3X2X1.03

(01)Case of Superspace particle,Density=10^36Kg/m^3

Velocity calculated using this relation is 3x10^8m/s,for Gravity force F=2.05x10^-38N at distance D/2=1x10^-35m=limiting gravity field of influence and mass=M=0.35x10^-50Kg.,there is a modification in equation (01),here V becomes (1/V)/173

Equation (01) can be applied for Motion with an extra application of force in case of non-relativistic motion.I case of relativistic motion.Equation takes the form

(m-m0)C^2=FxDx1.6…………..(02),where m is observed mass from Einstein’s relation of specila relativity and m0 is the rest mass.

         

REFERENCES:

 [1] FORCE RELATIONS

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  02/06/2015

   [2]Matter

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  24/10/2010

       [3]Radiation

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  24/10/2010

   [4]Energy

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  24/10/2010

(Munishkumar.B.Chinnakar)

 

     

VALIDITY OF NEWTON’S UNIVERSAL LAW OF GRAVIATION.

VALIDITY OF NEWTON’S UNIVERSAL LAW OF GRAVIATION.

NAME OF THEORETICAL PARTICLE ASTROPHYSICIST : MUNISHKUMAR.B.CHINNAKAR.

             

PLACE OF INVENTIONS: MUNISHKUMAR.B.C’S FIRST FLOOR BUILDING NEAR BHAIRI WELL BOYER STREET,SHORAPUR,PIN:585224 DIST:YADAGEER,KARNATAKA STATE INDIA.

                   

CO-WORKERS:NO CO-WORKERS.

DATE  OF INVENTIONS:N0V,2014 AND 24,JAN,2016

DATE  OF ENTRY OF INVENTIONS:JAN, 31,2016

PAPER NO: PAPFMJ/QGP 60/4415.

       Out of 74 types of Forces,Electric,Magnetic,Electromagnetic,Graviational

,Nuclear forces dominated the infinite Universe.These force are related to one another[1] and are further related[2] to temperature(separately in Hotter and Cooler zones).

After the creation of particle/body using self force , its constituents concentrates the free space outside of it with polarization(orientation of free space particles in one direction).Initial Zone is the zone of Nuclear force,next this is related to relaxed concentration like spherical zone of Electric field.Next to this a deviation in the spheroidal polarization as Ellipsoidal polarization,that is zone of ellipsoidal volume minus zone of Spheroidal volume is the zone of Magnetic field(this is more evident in motion) .If the density of the body is more like greater than 10^20Kg/m^3,then Graviational force between two particles is its 1D value like if F=x,then true gravitational force is F=(x)^1/4.This was proved and is having valid reasons and consistency.(more thedensity more will be the concentrated polarisation and hence 1D value)Therefore in case of Proton and proton gravity force is of the order 10^-15N,and that in between Electron and electron is of the order 10^-17N.These values are related to EM forces and hence to Nuclear forces.This indicates higher the density 1D value of 4D value will be the gravity force.This sets Drawback to Newton’s Universal law.If you use as such 4D value it will not relate to other forces.I used such types of conclusions just to support that minimum force in case of Particles should be greater than 10^-34N(maximum force should be less than 10^34N).Therefore this process gave accurate results.Therefore I modified[3] Newton’s law of gravitation in different situations during 2014.

From the above it is clear that Newton’s Univerasl gravitational law is valid only in free space for the force between two Material(not energetic,not radiational)bodies such that their density should be less than 10^12kg/m^3.This law is not valid in case of Radiational space/gravity space due to third body.There I used modifications.

If the density of the body is less than 10^20Kg/m^3 and more than 10^12Kg/m^3 then squre root of value calculated from Newton’s formula should be used as true value.

         

REFERENCES:

 [1] FORCE RELATIONS

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  02/06/2015

 [2] FORCE –TEMPRATURE RELATIONS

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  24/01/2016

[3]ACCELERATION DUE TO GRAVITY OF STARS-PHOTON STAR BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  06/11/2014

 

     

AT V=C

AT V=C

NAME OF THEORETICAL PARTICLE ASTROPHYSICIST : MUNISHKUMAR.B.CHINNAKAR.

             

PLACE OF INVENTIONS: MUNISHKUMAR.B.C’S FIRST FLOOR BUILDING NEAR BHAIRI WELL BOYER STREET,SHORAPUR,PIN:585224 DIST:YADAGEER,KARNATAKA STATE INDIA.

                   

CO-WORKERS:NO CO-WORKERS.

DATE  OF INVENTIONS:2005 AND JAN,25,2016

DATE  OF ENTRY OF INVENTIONS:JAN, 25,2016

PAPER NO: PAPFMJ/QGP 60/4415.

Most of the people are aware of the fact that pair produces and annihilates,at the same situation there lies facts at V=C.In olden days people used mass becomes infinite at V=C.This is not the case,here mass of kinetic energy becomes infinite one in Mathematical formulations,not the mass of Particle/Body.But nature opposes infinite nature for finite event but situates an infinite equivalent nature for the finite event.This is as follows.

A proton built with internal force of the order 10^6N may move with different strength force values.These strengths determines the velocity of the Proton.If a force of value 9.5x10^19N is applied to Proton then it moves with velocity V=C.This is consistent with equations of the form,

K.E=FxDx1.6,where F=1.9x10^24N and D= range[1] of EM force limit on either side =2.2x10^-13m,this gives K.E=6.7x10^10J.With this kinetic energy Proton moves with velocity V=3x10^8m/s.This is consistent with K.E=m.v.C,where m=mo/(1-V^2/C^2)^1/2,mo is the rest mass and m is the observed mass.

Here K.E=6.7x10^10J is the reciprocal of gravitated(C=10) rest mass energy,as 6.7x10^9x10=6.7x10^10J.The observed mass corresponding to this is 7.44x10^-7Kg.This is the mass of kinetic energy.This can be converted into mass of particle as 7.44x10^-7x(C=10^-20=transformation constant for energy from 1D to 4D)/(2x2x1.1)=1.66x10^-27Kg=rest mass of proton.This implies that at V=C mass is not becoming infinite but  it interacts itself to transform as Photon.This is consistent with 1D form of special relativistic equations.At the surface of Star like Sun ,temperature like 6x10^3K are promising as 4D value of this like 10^12K fits with hf=KT, at frequencies[2] like 0.5x10^23Hz such that hf becomes 1/hf with gravitating nature.

The above theory indicates one of the useful method which removes the Drawbacks occurring in Special relativity

         

REFERENCES: [1]MODEL OF HYDROGEN ATOM -QUALITATIVE

,BY MUNISHKUMAR.B.CHINNAKAR IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED   

: JUL,16,2011,JUL,21,2011

 [2] RADIATION

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED 24/10/2010

 

FORCE-TEMPRATURE RELATIONS

FORCE-TEMPRATURE RELATIONS

NAME OF THEORETICAL PARTICLE ASTROPHYSICIST : MUNISHKUMAR.B.CHINNAKAR.

             

PLACE OF INVENTIONS: MUNISHKUMAR.B.C’S FIRST FLOOR BUILDING NEAR BHAIRI WELL BOYER STREET,SHORAPUR,PIN:585224 DIST:YADAGEER,KARNATAKA STATE INDIA.

                   

CO-WORKERS:NO CO-WORKERS.

DATE  OF INVENTIONS:JAN14 to 24,2016

DATE  OF ENTRY OF INVENTIONS:JAN, 24,2016

PAPER NO: PAPFMJ/QGP 60/4414.

From the paper[1],it was clear that nuclear force varies with temperature,hence other forces[2] should vary with Temprature.This variation can be calculated as follows.

(01)Nuclear force and temperature relationship.

At the surface of star like Sun temperature is 6000K,therefore

dF_N/dT=43.02/6000=7.17x10^-3N/K………(01)

This is valid at temperature above 1721.66K and below  temperature 1.72166K.In between these two temperatures,Nuclear force is 1.2 N

(02)Electromagnetic and temperature relationship.

As nuclear force is 10^-3 times stronger than EM force,

dF_EM/dT=43.02/6000=7.17x10^-6N/K………(02)

(03)Gravity and temperature relationship

As Gravity is 4D force of EM force,

dF_G/dT=(7.17x10^-6)^4=2.642874x10^-21N/K………(03).This is consistent with 1D value of gravity of Proton and hence with maximum temperature of EM spectrum.

From relation (02) one can obtain the temperature relations of Electric force and Magnetic force.

         

REFERENCES: [1] GRAVITY FORCE AND NUCLEAR FORCE AT THE SURFACE OF STAR AND PLANET

,BY MUNISHKUMAR.B.CHINNAKAR IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  16/01/2016  

 [2] FORCE RELATIONS

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  02/06/2015