ACCELERATIONS OF PLANETS……AN APPLICATION OF EQUATIONS OF MOTIONS.

ACCELERATIONS OF PLANETS……AN APPLICATION  OF EQUATIONS OF MOTIONS.

NAME OF THEORETICAL PARTICLE ASTROPHYSICIST : MUNISHKUMAR.B.CHINNAKAR.

             

PLACE OF INVENTIONS: MUNISHKUMAR.B.C’S FIRST FLOOR BUILDING NEAR BHAIRI WELL BOYER STREET,SHORAPUR,PIN:585224 DIST:YADAGEER,KARNATAKA STATE INDIA.

                   

CO-WORKERS:NO CO-WORKERS.

DATE  OF INVENTIONS:05,MARCH,2016

DATE  OF ENTRY OF INVENTIONS:MARCH,20,2016
DATE  OF REENTRY OF INVENTIONS:MARCH,21,2016

PAPER NO: PAPFMJ/QGP 63/4418.

Equations of motions as described by Newton were correct but as such force quation will not describe anything regarding force distribution during motion.Further they are not correctly describing the acceleration of Planets.Therefore My modified equations of Motions[1] are useful.These modified equations of motions can be used to calculate rotational acceleration and revolving acceleration of different Planets around Star(The values calculated are consistent with other equations of motion like centripetal/centrifugal motions).This is as follows.

(A)REVOLVING ACCELERATION OF PLANET

The planet revolves around a star like Sun due to gravity field of Star(when it is alone it would have been moved due to self motion).Here it chooses the value like acceleration due to gravity of star at the place of Planet.In case of earth[2] it is 6km/S^2.The force which it moves this planet is related to its velocity[3] by the following equation.

             1/2(MV^2)=FxDx1.6…………(01)

This gives a force F=[1/2(MV^2)]/Dx1.6.But this force is purely gravitational but in presence of Star’s Radiation this becomes

F=[1/2(MV^2)]x10^3/Dx1.6………..(02)

In case of Earth,m=5.9x10^24kg,V=revolving velocity of Earth around Sun=30km/s=3x10^4m/s,D=gravity field limiting value of earth3.5x10^8m.Therefore using (02) force becomes 2.37x10^27N.

This is the real force with which a Planet like Earth revolves around the Sun.The acceleration of Planet during its revolving motion can be calculated using equation

Revolving acceleration of Planet=a= F/M………(03),

where F is the value from equation (02).Thus in case of Earth a=2.37x10^27N/5.9x10^24kg=4.01x10^2m/s^2

The Earth is revolving around the Sun with acceleration 4.01x10^2m/s^2.Thus using equation (03) with modification as in (02) can be used for the calculation of revolving acceleration of a Planet around Star.

(B)ROTATIONAL ACCELERATION OF PLANET

The planet rotates around itself .Here it chooses the value likerotational velocity of planet.In case of earth it is 436m/S.The force which it rotates this planet is related to its roational velocity by the following equation.

             1/2(MV^2)=FxDx1.6…………(04)

This gives a force F=[1/2(MV^2)]/Dx1.6.But this force is purely gravitational but in presence of Star’s Radiation this becomes

F=[1/2(MV^2)]x10^3/Dx1.6………..(05)

In case of Earth,m=5.9x10^24kg,V=rotational  velocity of Earth around itself=436m/s=,D=Diameter of Earth=1.2x10^7m.Therefore using (05) force becomes 2.9069x10^25N.

This is the real force with which a Planet like Earth rotates around itself.The acceleration of Planet during its rotational motion can be calculated using equation

Rotating acceleration of Planet=a= F/M………(06),

where F is the value from equation (05).Thus in case of Earth a=2.9069x10^27N/5.9x10^24kg=4.9503m/s^2

The Earth is rotatinging around itself with acceleration 4.950m/s^2.Thus using equation (06) with modification as in (05) can be used for the calculation of rotational acceleration of a Planet itself.

This acceleration like 4.950m/s^2 links to the value like acceleration due to gravity of earth.Here inertia of Earth acts and reacts(2) yielding a value like 4.950x2=9.8m/s^2,here gravity interaction like 1.1 is taken into account.Therfore the value of g for Earth is 9.8m/s^2

Above method of Calculation is useful for calculations of accelerations of different planets around Star.However 1D nature of Planet some times is a need for 1D planets.In the above accelerations for 4D acceleration like 401 m/s^2,4D value of acceleration due to gravity adds such that 401+(4x9.8)-4=436.2m/s^2.Thus revolving acceleration of Earth acts as rotational velocity.Therefore actually revolving acceleration oscillates and its interaction with g rotates the Earth.Therefore Spinning nature is not an Intrinsic property.

NOTE:Equations (03) and (06) are consistent with equations like MV^2/R=F=Mxa (with modification to this for consistency using useful reasons).In the above example of Earth,in case of (A) MV^2/R  can be modified as (4x10^3x10x10/2π)xMV^2/R.In case (B) (2π/2) x(10x10)xMV^2/R

         

         

REFERENCES:

[1] EQUATIONS OF MOTIONS

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  07/03/2016

  [2] ACCELERATION DUE TO GRAVITY OF STARS-PHOTON STAR

,BY MUNISHKUMAR.B.CHINNAKAR   IN HIS ONLINE JOURNAL/SITE /BLOGGER IN GOOGLE DATED  06/11/2014

   [3]EARTH,BY WIKIPEDIA,UPDATED DURING 2016