CONDITION FOR REVOLVING HENCE ROTATING MOTION

CONDITION FOR REVOLVING HENCE ROTATING MOTION

NAME OF SCIENTIST: MUNISHKUMAR.B.CHINNAKAR.

PLACE OF INVENTIONS: MUNISHKUMAR'S PLACE OF INVENTIONS,NEAR BHAIRI WELL BOYER STREET(BHOVI STREET),SHORAPUR,KARNATAKA STATE,INDIA.

E-mail:www.MChinnakar@gmail.com.

NUMBER OF CO-WORKERS : No co-workers.

DATE OF INVENTION: 22 Dec,2015

DATE  OF ENTRY  OF  INVENTIONS: 23/12/2015

NUMBER:PAPFMJ/QPP255 /4411

A body revolves around another body due to fact that it should have sufficient gravitational/Electromagnetic Interactions such that it should obey 3/2 body problem with the consideration of field as body.A body left in free space moves itself because it is having ellipsoidal shaped configuration of gravity field.As this gravity field interacts with free space field then to obey action as reaction it moves.

For the motion of a body around another,its ellipsoidal configuration of gravity/EM field should interact with gravity/EM field of another.Here gravity gravity interaction produces EM nature.This indicates all along the revolving motion EM nature should be evident at least in equations.Thus a condition is generated,that is Ratio of mass per unit length of revolving body(like  planet) to distance of revolving body from another body(like Sun) is greater than 10^3Kg/m^2.If this is not true then body is not revolving[1].For example in case of  particles like Electrons in an atom,here Electrons are not revolving because it is not fulfilling the above condition.

A body subjected to revolving motion with respect to another body may rotate itself(like planet) due to variation of Ellipsoidal configuration of field around itself caused by the interaction of the field of another body(like Sun).This roational motion yields the spin.Elementary particles are not rotating around themselves,but may freely move in free space.Any spin if you assign like 1/C^2,C,1/C^3 to particles it mearly mean that you assigned for vibrational velocity such that you can use reciprocal value of this in calculation for consistency.

Then spin nature of particles is not useful in  distinguishing of Matter from antimatter.However system values  like 1/C^2,C,1/C^3 can be used to distinguish.However you can consider Positively charged Particles as material particles and negatively charged particle of same value like mass as antiparticle.Most of the Neutral radiational particles are their antiparticles.Here you can distinguish the particle and antiparticle nature based of the situation of origin(here usually particle associates with positive charged main particle and antiparticle associates with negatively charged particle on the same side of the Elemenatary particle reactions).

Ceratin neutral particles like neutron are differeing from their antiparticles in their internal structures.However Photon/graviton are strictly their own antiparticles.

REFERENCES                                                                                                      

[1]IN THE MODIFIED ATOMIC MODEL, BY MUNSIHKUMAR.B.CHINNAKAR PUBLISHED IN HIS ONLINE JOURNAL OF PARTICLE ASTROPHYSICS/ASTROSCIENCE /BLOGGER/SITE IN GOOGLE DATED 20,21/12/2015

NUMBER OF ELECTRONS IN DIFFERENT SHELLS IN MODIFIED ATOMIC MODEL

NUMBER OF ELECTRONS IN DIFFERENT SHELLS IN MODIFIED ATOMIC MODEL

NAME OF SCIENTIST: MUNISHKUMAR.B.CHINNAKAR.

PLACE OF INVENTIONS: MUNISHKUMAR'S PLACE OF INVENTIONS,NEAR BHAIRI WELL BOYER STREET(BHOVI STREET),SHORAPUR,KARNATAKA STATE,INDIA.

E-mail:www.MChinnakar@gmail.com.

 NUMBER OF CO-WORKERS : No co-workers.

DATE OF INVENTION: 22 Dec,2015 

DATE  OF ENTRY  OF  INVENTIONS: 22/12/2015 

NUMBER:PAPFMJ/QPP255 /4410

In modified Bohr’s atomic model[1],the first shell uses only two electrons.In old theory it was assumed as due to two possible spin states like ½ and -1/2 for Electrons.But Electrons are not spinning when they are alone,they are simply vibrating with their frequencies at rest.The spin state can be equivalently differentiated as two separate location one at bulging position and another at non-bulging position.This is the state of Electrons in first shell.Then a question arises why only two Electrons in first shell.According to modified method this is due the fact of available volume of Electric field of influence of Nucleus in first shell after the balance by radiation pressure effect.Such a available volume is just a  Ellipsoidal shell within Ellispoidal field of Nucleus.This volume is 1x10^-36m^3.The volume of Electron’s field of influence is 2.378x10^-36m^3.The ratio like 2.378x10^-36/1x10^-36m^3=2.378=two Electrons in the shell n=1.Here without spin state this modified model gives a meaning for Pauli’s exclusion principle’s consequences.

Next comes n=2,here there is a possibility of occupation of two electrons near the two edges of semiminor axis.This position can be considered as s orbital.next p orbital positions can be considered near by semimajor axis.In case of n=2,s takes 2 electrons and p takes 6 electrons,thus atotal of 8 Electrons.This is can be proved using volume available. volume of Electric field of influence of Nucleus in second shell after the balance by radiation pressure effect.Such a available volume is just a  Ellipsoidal shell within Ellispoidal field of Nucleus and is 0.081x10^-36m^3. The volume of Electron’s field of influence is0.6567x10^-36m^3.Their ratio gives 0.6567x10^-36m^3/0.081x10^-36m^3=8.107=eight electrons.Like this way according to n=1,2,3,4,5,6,7 number of electrons varies near semiminor axis(s orbits) and other positions like p,d,f orbitals

From the above it is clear that quantization(n) of energy of electrons is related to energy of field of Nucleus via available volume of electric field of nucleus with the consideration of radiation pressure of different electrons.This is because I used n in case of radii calculation which is used in available volume calculations

REFERENCES                                                                                                         

 [1]IN THE MODIFIED ATOMIC MODEL, BY MUNSIHKUMAR.B.CHINNAKAR PUBLISHED IN HIS ONLINE JOURNAL OF PARTICLE ASTROPHYSICS/ASTROSCIENCE /BLOGGER/SITE IN GOOGLE DATED 20,21/12/2015

ABOUT MODIFIED ATOMIC MODEl

ABOUT MODIFIED ATOMIC MODEL

NAME OF SCIENTIST: MUNISHKUMAR.B.CHINNAKAR.

PLACE OF INVENTIONS: MUNISHKUMAR'S PLACE OF INVENTIONS,NEAR BHAIRI WELL BOYER STREET(BHOVI STREET),SHORAPUR,KARNATAKA STATE,INDIA.

E-mail:www.MChinnakar@gmail.com.

 NUMBER OF CO-WORKERS : No co-workers.

DATE OF INVENTION: 2011,20 Dec,2015 

DATE  OF ENTRY  OF  INVENTIONS: 20/12/2015 

DATE  OF REENTRY  OF  INVENTIONS: 21/12/2015,25/1/2016 

NUMBER:PAPFMJ/QPP254 /4409

I modified Extended Bohr’s Atomic  model such as force equivalence in the calculation of centripetal force=MV^2/R=FX10^-3…….(01)

,V is the reciprocal value of {vibrational velocity of electron at restX (2X3X10^-1)},here this velocity (tremor velocity) of electron=1.1X10^-11m/s(in free space),as electrons are not revolving around nucleus.The modified Bohr’s quantum condition is

 MVR=nh/ 2π ……..(02),where V=(1/vibrational velocity of electron)/(3x3x10)

 I further modified vector atom model.

 In the above modification I used reciprocal tremor velocity because  electron is not revolving,if I consider it as moving then I should use reciprocal value for consistency.Further as gravity is responsible for motion,gravitating nature(C=10=1) with action reaction pair(3x2=1) should be used.In the modified Bohr’s quantum condition,I used 2π=2x3.142 to show elliptic nature of orbit 

The above relations are consistent with formulation and gives average radius[1] of first Bohr’s orbit as r₁=1.1x10^-13m(This is consistent with Radius of Proton=1.1x10^-17m=1.1x10^-16x10^4=1.1x10^-13m=Electric field influence range of Proton) or diameter as D₁=2.2x10^-13m.The Elliptic value of diameter is D₁’=13.824x10^-13m.If an electron in one orbit is located at a distance 1.1x10^-13m then another electron is located at a distance r’_n =6.912x10^-13m.At a distance   r_n=1.1x10^-13m,energy is E1=13.6eV=2.176x10^-18j.Therefore at a distance  r’_n =6.912x10^-13m energy is  E1’=3.6x1009x10^-18j(here diameter is used to calculate energy,obvious in next orbit calculation)This obeys E_n   =(Z^2xE1)/n^2……….(03) and E_n ‘  =(Z^2xE1’)/n^2.

In the above calculation r_n  =r₁xn/Z………(04),where n=1.2.3.4.5,6,7

As Electrons are not revolving/rotating ,its spin nature can be considered as such but with condition using tremor velocity.

Explainations:

(01)This modified Model explains why electron is not moving.This is because when Electron approaches the Electric field of Nucleus the opposite polarization charges of the fields produces Electromagnetic fields.These fields produces radiation pressure.As the Electric nature drags the Electron towards Nucleus,radiation pressure pushes away from it up to a certain distance say 4.5x10^-13m.This is because, radius of electron x10^3=4.5x10^-19x10^2=4.5x10^-17m=electric field influence limiting value=4.5x10^-16x10^4=Electromagnetic effect correction due to radiation pressure=4.5x10^-13m.this is nearly equal to distance separation between one orbit to next orbit =D1-D2=4.608x10^-13m.This is the reason for electron gap between one electron to next electron in another orbit.

(02)The separation distance between one Electron to another in the same orbit indicates the effect of radiation pressure in situating 3/2 body problem.This is because 6.99x10^-13m/4.5x10^-13m=3/2.

(03)This model explains spin as due to tremor energy of particle and not due to rotation.This is evident from the value like energy difference between two Electrons in one orbit=1.208x10^-18J.If you submit the Electric/Magnetic field then it Polarises the fields of Electrons to yield radiation which changes the positions or flips.Thus 1.208x10^-18x4x2x10^-3x10^-3=9.7x10^-24j=spin flip flop energy[here energy was given and taken(10^-6) twice as action reaction pair(4x2)].

(04)This Model helps to explain why Neutron is having spin magnetic moment eventhough it is neutral

(05) This model explains the stability of Electron not to ionize itself in orbit/shell configuration.This is evident from relation dE=(dDx10^-5)/3.7,where dE=1.208x10^-18j and dD=4.6x10^-13m=twice the difference between the distances of Electrons(n=1,n=2 orbits) from nucleus.Here the value 3.7 is divided indicating stability of Energy with respect to space of Electron’s Shell.

(06)This model explains the Superconductivity origin[2]

REFERENCES                                                                                                         

[1] STRUCTURE OF HYDROGENATOM,BY MUNSIHKUMAR.B.CHINNAKAR PUBLISHED IN HIS ONLINE JOURNAL OF PARTICLE ASTROPHYSICS/ASTROSCIENCE /BLOGGER/SITE IN GOOGLE DATED 24/7/2011

[2]IN THE MODIFIED ATOMIC MODEL,AN EXPRESSION FOR COOPER PAIRING ENERGY BY MUNSIHKUMAR.B.CHINNAKAR PUBLISHED IN HIS ONLINE JOURNAL OF PARTICLE ASTROPHYSICS/ASTROSCIENCE /BLOGGER/SITE IN GOOGLE DATED 20,19/12/2011

IN THE MODIFIED ATOMIC MODEL,AN EXPRESSION FOR COOPER PAIRING ENERGY

IN THE MODIFIED ATOMIC MODEL,AN EXPRESSION FOR COOPER PAIRING ENERGY

NAME OF SCIENTIST: MUNISHKUMAR.B.CHINNAKAR.

PLACE OF INVENTIONS: MUNISHKUMAR'S PLACE OF INVENTIONS,NEAR BHAIRI WELL BOYER STREET(BHOVI STREET),SHORAPUR,KARNATAKA STATE,INDIA.

E-mail:www.MChinnakar@gmail.com.

OR

www.mchinnakar@gmail.com

 NUMBER OF CO-WORKERS : No co-workers.

DATE OF INVENTION: Dec,10,2015 

DATE  OF ENTRY  OF  INVENTIONS: Dec,19,2015 

DATE  OF REENTRY  OF  INVENTIONS: Dec,20,21,2015 

I MODIFIED  EXTENDED BOHR'S MODEL SUCH AS FORCE EQUIVALENCE,IN THE CALCULATION OF CENTRIPETAL FORCE MV^2/R=FX10^-3,V IS THE RECIPROCAL VALUE OF {TREMOR VELOCITYX(2X3X10^-1)},HERE TREMOUR VELOCITY OF ELECTRON=1.1X10^-11M/S,AS ELCTRONS ARE NOT REVOLVING ARROUND NUCLEUS AND MVR=(nh/2X3.142),WHERE V=(1/VIBRATIONAL VELOCITY OF ELECTRON)/(3X3X10).I FURTHER  MODIFIED  VECTOR ATOM MODEL,AN EXPRESSION TO PAIRING ENERGY IN SUPERCONDUCTING COOPER PAIR CAN BE GIVEN AS dE=(dDX10^-5)/(4x2),WHERE dE IS THE DIFFERENCE BETWEEN ENERGY OF TWO ELECTRONS IN ONE ORBIT[1] AND dD IS TWICE THE DIFFERENCE IN THE DISTANCE BETWEEN ELECTRONS AND NUCLEUS IN SUPERCONDUCTING STATE,EXAMPLE IN CASE OF COOPER PAIR  dD=11.6028X10^-13x(10^-3=C=1)=11.6028x10^-16M,dE=1.43X10^-18x(10^-3=C=1)=1.43x10^-21J.THIS VALUE IN TERMS OF eV=8.9375X10^-3eV.THIS THE ENERGY WHICH BINDS THE COOPER PAIR[2].

NOTE:IN THE BOHR'S MODIFICATION, I USED 10^-3 FACTOR TO DISTINGUISH BETWEEN ELECTRIC AND ELECTROMAGNETIC FORCE,BETWEEN ELECTRON AND PROTON,FORCE TURNS TO BE ELECTROMAGNETIC INSTAED OF ELECTRIC.

NOTE:HERE DIFFERENCE IN ENERGY OF ELECTRON WITHIN THE SAME ORBIT ARISES BECAUSE LOCATION OF ELECTRON AT BULGING POSITION IS DIFFERENT FROM NON-BULGING POSITION IN AN ELLIPSOIDAL CONFIGURATION OF FIELD OF NUCLEUS. THE TWO ELECTRONS SEPERATES BY A DISTANCE =1/C^2 =10^-16=11.6028x10^-16/10 AS ELECTRONS ANTIGRAVITATES DURING PAIR FORMATION,(WHERE C=10^8=1=A TRANSFORMATION CONSTANT OF UNITY TYPE) BECAUSE OF RADIATION PRESSURE EFFECT OF VIRTUALLY NEUTRAL CHARGED EM FIELD GENERATED BETWEEN ELECTRON AND PROTON IN SUPERCONDUCTING STATE.THUS GAP EXISTS EVEN BETWEEN TWO ELECTRONS.

REFERENCES:

[1]ELLIPSOIDAL CONFIGURATION AS IN STRUCTURE OF HYDROGEN MOLECULE,BY MUNSIHKUMAR.B.CHINNAKAR PUBLISHED IN HIS ONLINE JOURNAL OF PARTICLE ASTROPHYSICS/ASTROSCIENCE /BLOGGER/SITE IN GOOGLE DATED 25/7/2011

[2] COOPER PAIRS,AS IN WIKIPEDIA UPDATED DURING 2015 (MUNISHKUMAR.B.CHINNAKAR, COOPER PAIRING ENERGY, 2015)